Aptitude - Pipes and Cistern

6.

A tap can fill a cistern in 8 hrs and another tap can empty it in 16 hrs. If both the taps are open, the time taken to fill the tank will be :

Answer

Answer :

Option C

Explanation :


Part filled by both pipes in 1 min = 18116 = 116
Total time taken to fill the tank = 16 hrs.
7.

Pipes A and B can fill a tank in 20 hrs and 30 hrs respectively and pipe C can empty the full tank in 40 hrs. If all the pipes are opened together how much time will be needed to make the tank full ?

Answer

Answer :

Option C

Explanation :


Net part filled in 1 hr = 120 + 130140 = 7120
Time needed to make the tank full = 1207 hrs = 1717 hrs.
8.

A larger tank can be filled by two pipes A and B in 60 minutes and 40 minutes respectively. How many minutes will it take to fill the tanker from empty state if B is used for half the time and A and B fill it together for the other half ?

Answer

Answer :

Option D

Explanation :


Let the total time taken be x minutes. Then,
140 x x2 + 160 + 140 x2 = 1
x80 + x48 = 1
3x + 5x = 240 8x = 240 x = 30
Hence, time required is 30 minutes.
9.

Two pipes A and B can fill a tank in 1 hr and 75 min respectively. There is also an outlet C. If all the three pipes are opened together, the tank is full in 50 minutes. How much time will be taken by C to empty the full tank ?

Answer

Answer :

Option C

Explanation :


Work done by C in 1 min = 160 + 175150 = 3300 = 1100
Hence, C can empty the full tank in 100 minutes.
10.

A pipe can fill a cistern in 12 minutes and another pipe can fill it in 15 minutes. But, a third pipe can empty it in 6 minutes. The first two pipes are kept open for 5 minutes in the begining and then the third pipe is also opened. In what time is the cistern emptied ?

Answer

Answer :

Option D

Explanation :


Part filled in 5 min = 5 x 112 + 115 = 5 x 960 = 34
Part emptied in 1 min when all the pipes are opened
= 16 112 + 115 = 16320 = 160
160 part emptied in 1 min.
34 part will be emptied in 60 x 34 min = 45 min.
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